For calculating the quantities of cement,sand and aggregates required for 1㎥ for Nominal mixes as:
M-10
M-15
M-20
M-25  (Nominal mix) 




Let me show you how to calculate the quantities for above Nominal mixes one by one as under:


1.Concrete mix design for M-10 (1:3:6) grade of concrete:

As we know that when we pour wet concrete during concreting, it hardens after certain standard time. In view of this, it was decided by the Civil Design Engineers to take a factor of safety from 1.54 to 1.57 .

 so we can say, Volume of dry concrete = 1.54 to 1.57 times the volume of wet concrete

 I m assuming 1.54 as a safety factor

 Therefore, the total volume of concrete required is 1.54.

 As per IS456:2000, M-10 Grade concrete proportion is  = 1 :  3 : 6

Remember, here  (1:3:6)  indicates:

1 for cement

3 for sand

6 for aggregate

Total volume (cement + sand + aggregate) = 1 +  3 + 6= 10

Calculation of Volume of Cement in 1  of Concrete

 Volume of cement= (cement/cement+sand+aggregate) x 1.54

 Quantity of cement=  (cement/total volume) x1.54

                              =  (1/10)x1.54

                              =  0.154 

 we know , Volume of a one cement bag =0.0347

 Thus Total  no. of bags required for 1 = 0.154/0.0347

                                                            = 4.52   bags


Hence, we require 4.52 bags of cement for 1 cu.m of concrete.


As we know,  1 Bag of cement weighs 50 kg (one bag of cement)

so For 1 of concrete we have ,

Total  no. of bags required x 50 kg of cement = 4.52 x 50 = 226 kg


For 1
 of Concrete = 226 Kgs of Cement is required.

 

Calculation of Volume of Sand (Fine Aggregate) in  1 of Concrete:

Volume of sand= (sand/cement+sand+aggregate) x 1.54

Quantity of sand =  (sand/total volume) x1.54

                               =  (3/10)x1.54

                               =  0.462 

1 of sand = 1600-1800 kg 

Assume 1600 kg

 0.462  of sand =1600 x 0.462 

                        = 739 kg

 The volume of sand increases as it contains moisture.For accurate calculation use dry sand.

Hence we require 739 kg of sand  for 1 cu.m of concrete.


Calculation of Volume of Coarse Aggregate in 1 of Concrete:-

Volume of aggregate= (aggregate/cement+sand+aggregate) x 1.54

Quantity of aggregate=  (aggregate/total volume) x1.54

                                      =  (6/10)x1.54

                                       =  0.924 

1 of aggregate = 1500-1800 kg 

Assume 1500 kg

 0.924  of aggregate =1500 x 0.924

                        = 1386 kg

 If void spaces decreases,density of aggregate may go higher. 

Hence we require 1386 kg of aggregates (20 mm)  for 1 cu.m of concrete.


Water  required for 1  of concrete: -

Water is added for making the concrete mass and it depends upon the climatic conditions whether hot or cold weather and workability.

We typically maintain a 0.35–0.50 to water cement ratio. Remember, the above values may change according to the moisture content present in the sand and aggregates.

Cement Required for 1of Concrete  = 226 Kgs

Assume W/C ratio = 0.45 

Water required for 1 of Concrete = 226 x 0.45

Amount of water required for 1 of Concrete = 102 kgs = 102 litres.

Hence 180 Litres of Water is required for 1 of M10 Concrete.


2.Concrete mix design for M-15 (1:2:4) grade of concrete:

Remember, here  (1:2:4)  indicates:

1 for cement

2 for sand

4 for aggregate

Total volume (cement + sand + aggregate) = 1 +  2 + 4= 7

Calculation of Volume of Cement in 1  of Concrete

Volume of cement= (cement/cement+sand+aggregate) x 1.54 

Quantity of cement=  (cement/total volume) x1.54

                              =  (1/7)x1.54

                              =  0.22 

 we know , Volume of a one cement bag =0.0347

 Thus Total  no. of bags required for 1 = 0.22/0.0347                

                                                              = 6.47   bags

Hence, we require 6.47 bags of cement for 1 cu.m of concrete.

 As we know,  1 Bag of cement weighs 50 kg (one bag of cement)

 so For 1 of concrete we have ,

 Total  no. of bags required x 50 kg of cement = 6.47 x 50 = 324 kg

For 1 of Concrete = 324 Kgs of Cement is required.

 

 Calculation of Volume of Sand (Fine Aggregate) in  1 of Concrete: 

Volume of sand= (sand/cement+sand+aggregate) x 1.54 

Quantity of sand =  (sand/total volume) x1.54

                               =  (2/7)x1.54

                               =  0.44 

1 of sand = 1600-1800 kg 

Assume 1600 kg

0.44 of sand =1600 x 0.44 

                        = 704 kg

Hence we require 704 kg of sand  for 1 cu.m of concrete.


Calculation of Volume of Coarse Aggregate in 1 of Concrete:-

Volume of aggregate= (aggregate/cement+sand+aggregate) x 1.54

Quantity of aggregate=  (aggregate/total volume) x1.54 

                                       =  (4/6)x1.54

                                       =  0.88 

1 of aggregate = 1500-1800 kg 

Assume 1500 kg

0.88 of aggregate =1500 x 0.88

                        = 1320 kg

Hence we require 1320 kg of aggregates (20 mm)  for 1 cu.m of concrete.


Water  required for 1  of concrete: - 

Cement Required for 1of Concrete  = 324 Kgs

Assume W/C ratio = 0.45 

Water required for 1 of Concrete = 324 x 0.45

Amount of water required for 1 of Concrete = 102 kgs = 146 litres.

Hence 180 Litres of Water is required for 1 of M15 Concrete.

 

3.Concrete mix design for M-20 (1:1.5:3) grade of concrete

For that article click M-20 Mixcalculation.

 

4.Concrete mix design for M-25 (1:1:2) grade of concrete:

Remember, here  (1:1:2)  indicates:

1 for cement

1 for sand

2 for aggregate

Total volume (cement + sand + aggregate) = 1 +  1 + 2= 4

Calculation of Volume of Cement in 1  of Concrete

Volume of cement= (cement/cement+sand+aggregate) x 1.54

Quantity of cement=  (cement/total volume) x1.54

                              =  (1/4)x1.54

                              =  0.385  

we know , Volume of a one cement bag =0.0347

Thus Total  no. of bags required for 1 = 0.308/0.0347                 

                                                              = 11.3   bags

Hence, we require 9.05 bags of cement for 1 cu.m of concrete.

As we know,  1 Bag of cement weighs 50 kg (one bag of cement)

so For 1 of concrete we have ,

Total  no. of bags required x 50 kg of cement = 11.3 x 50 = 565 kg

For 1 of Concrete = 565 Kgs of Cement is required.


Calculation of Volume of Sand (Fine Aggregate) in  1 of Concrete:

 Volume of sand= (sand/cement+sand+aggregate) x 1.54 

Quantity of sand =  (sand/total volume) x1.54

                               =  (1/4)x1.54

                               =  0.385 

1 of sand = 1600-1800 kg 

Assume 1600 kg

0.385  of sand =1600 x 0.385 

                        = 616 kg

Hence we require 616 kg of sand  for 1 cu.m of concrete.


Calculation of Volume of Coarse Aggregate in 1 of Concrete:-

 Volume of aggregate= (aggregate/cement+sand+aggregate) x 1.54

 Quantity of aggregate=  (aggregate/total volume) x1.54

                                       =  (2/4)x1.54

                                       =  0.77

1 of aggregate = 1500-1800 kg 

Assume 1500 kg

0.77 of aggregate =1500 x0.77

                        = 1155 kg

 Hence we require 1155 kg of aggregates (20 mm)  for 1 cu.m of concrete.


Water  required for 1  of concrete: -

 Cement Required for 1of Concrete  = 565 Kgs

Assume W/C ratio = 0.45 

Water required for 1 of Concrete = 565 x 0.45

Amount of water required for 1 of Concrete = 254 kgs = 254 litres.

Hence 254 Litres of Water is required for 1 of M25 Concrete.

 

Summary: –

M-10 grade. concrete. 

4.52 bags of cement required for 1 cu.m of M-10 grade. concrete. 

739 kg of Sand required for 1 cu.m of M-10 grade concrete. 

1386 kg of 20mm Aggregate is required for 1 cu.m of M-10 grade concrete.

102 litres of water is required for 1 cu.m of M-10 grade concrete


M-15 grade. concrete

6.47  bags of cement required for 1 cu.m of M-15 grade. concrete. 

704 kg of Sand required for 1 cu.m of M-15 grade concrete. 

1320 kg of 20mm Aggregate is required for 1 cu.m of M-15 grade concrete.

146 litres of water is required for 1 cu.m of M-15 grade concrete.


M-20 grade. concrete

8 bags of cement required for 1 cu.m of M-20 grade. concrete. 

693 kg of Sand required for 1 cu.m of M-20 grade concrete. 

1344 kg of 20mm Aggregate is required for 1 cu.m of M-20 grade concrete.

180 litres of water is required for 1 cu.m of M-20 grade concrete.

 

M-25 grade. concrete

11.3  bags of cement required for 1 cu.m of M-25 grade. concrete. 

616 kg of Sand required for 1 cu.m of M-25 grade concrete. 

1155 kg of 20mm Aggregate is required for 1 cu.m of M-25 grade concrete.

254 litres of water is required for 1 cu.m of M-25 grade concrete.

 

Number of Cement bags, Sand and Aggregate required for different Concrete Grade mixes in Kgs
Concrete grades with all constituents
Concrete grades with all constituents


Number of Cement bags, Sand and Aggregate required for different Concrete Grade mixes in cft 


Grade mixes in cft
Concrete Grade mixes in cft 

The initial concrete grades are best used for:

M 10

Used for: Patio slabs, pathways,Pcc and non-structural work.

Type: Domestic & commercial use.

M 15

Used for: Pavement kerbs and floor blinding.

Type: Domestic & Commercial.

M 20

Used for: Domestic floors and foundations (where the weight of structure will be lighter). Also good for workshop bases, garages, driveways and internal floor slabs.

Type: Domestic.

M 25

Used for: Construction in all areas. Multi-purpose concrete mix, usually used for foundations.

Type: Domestic & Commercial.




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